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Multiply 9/14x2/15
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3/28
\(\frac{9}{14} \cdot \frac{2}{15} = \frac{3 \cdot 3}{7 \cdot 2} \cdot \frac{2}{3\cdot 5} = \frac{3}{7 \cdot 35} = \frac{3}{35}\)
i wonder why the latex isn't working for me is it working for you guys?
Well that failed. The trick to this problem is to cancel common factors in the numerator and denominator. 9/14 = (3*3)/(7*2) and 2/15 = 2/(3*5) When multiplying fractions, we multiply the numerators times the numerators and the denominators times the denominators, and cancel like factors wherever they appear: (3*3*2)/(7*2*3*5) Notice that we have a 3 and a 2 canceling which leaves us with: 3 / (7*5) which is just 3/35.
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