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Mathematics 16 Online
OpenStudy (anonymous):

Can someone solve the equation attached?

OpenStudy (anonymous):

OpenStudy (anonymous):

Again! Haha.

OpenStudy (anonymous):

I only have a couple more

OpenStudy (anonymous):

Does this mean no?

OpenStudy (anonymous):

It means I'll do what I can. But Help Monkeys also need some rest :-)

OpenStudy (anonymous):

sorry, I hate to bug

OpenStudy (anonymous):

Let's call the year 1920 the year t=0. This means that 1990 is the year t=70. \[R(0)=46.4\]\[R(70)=44.3\]You have two points, (0, 46.4) and (70, 44.3). The first step is almost always finding slope. Find the slope using the equation \[m=\frac{y_2-y_1}{x_2-x_1}\] \[m=\frac{(46.4)-(44.3)}{(0)-(40)}\]\[m=-0.03\] Then find the y-intercept. The y-intercept happens where the t-coordinate is 0, so b=46.4. \[y=-0.03t+46.4\] That's your linear function. Let me know if you need more on the next two parts.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

there was one part missing in what year will the predicted record be 43.76 seconds?

OpenStudy (anonymous):

c) 2008

OpenStudy (anonymous):

You want to know what t is when R is 43.76. \[43.76=-0.03t+46.4\]Solve for t.

OpenStudy (anonymous):

Did anyone get what the seconds would be for 2003 and 2006?

OpenStudy (anonymous):

Great, I was forgotten

OpenStudy (anonymous):

2003: 43.91 2006: 43.82

OpenStudy (anonymous):

so what did R(t)=?

OpenStudy (anonymous):

Which suestion?

OpenStudy (anonymous):

In the beginning of the series of questions, it ask R(t)=

OpenStudy (anonymous):

before it asked for the predictions for the years

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