Can someone solve the equation attached?
Again! Haha.
I only have a couple more
Does this mean no?
It means I'll do what I can. But Help Monkeys also need some rest :-)
sorry, I hate to bug
Let's call the year 1920 the year t=0. This means that 1990 is the year t=70. \[R(0)=46.4\]\[R(70)=44.3\]You have two points, (0, 46.4) and (70, 44.3). The first step is almost always finding slope. Find the slope using the equation \[m=\frac{y_2-y_1}{x_2-x_1}\] \[m=\frac{(46.4)-(44.3)}{(0)-(40)}\]\[m=-0.03\] Then find the y-intercept. The y-intercept happens where the t-coordinate is 0, so b=46.4. \[y=-0.03t+46.4\] That's your linear function. Let me know if you need more on the next two parts.
ok
there was one part missing in what year will the predicted record be 43.76 seconds?
c) 2008
You want to know what t is when R is 43.76. \[43.76=-0.03t+46.4\]Solve for t.
Did anyone get what the seconds would be for 2003 and 2006?
Great, I was forgotten
2003: 43.91 2006: 43.82
so what did R(t)=?
Which suestion?
In the beginning of the series of questions, it ask R(t)=
before it asked for the predictions for the years
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