4x^2 =12 solve using radicals,rationalize all denominators express complex numbers in terms of i or use a comma to separate answers if needed then find the x intercepts

Question

zarkon · Answer

divide by 4 from both sides...take square root of both sides

anonymous · Answer

ok well is this for the first part or the second part and can you show me what you mean please

zarkon · Answer

$$4x^2=12$$

$$\frac{4x^2}{4}=\frac{12}{4}$$

$$x^2=3$$

$$x=\pm\sqrt{3}$$

anonymous · Answer

so there are two solutions to thisa problem ?

zarkon · Answer

yes

anonymous · Answer

ok whar the other one$$\sqrt{-3}$$

zarkon · Answer

$$\sqrt{3}\cdot i$$

zarkon · Answer

?

anonymous · Answer

i see sorry i was going by some past answers im really struggling with this

anonymous · Answer

wait i tried your answer and then it said mine was right but i write it wrong$$-\sqrt{3}$$

zarkon · Answer

there are two answers to the original problem you posted

$$\sqrt{3}$$ and $$-\sqrt{3}$$

as i had posted above

$$\pm\sqrt{3}$$

anonymous · Answer

i misunderstood im sorry

zarkon · Answer

That's ok :)

anonymous · Answer

so if i were to apply what you showed me then 5x^2=10 would be similar

zarkon · Answer

yes..divide by 5 first

then take square root
you will get two solutions

anonymous · Answer

i would get $$\sqrt{2},-\sqrt{2}$$

zarkon · Answer

yes

anonymous · Answer

then my intercepts should be $$\sqrt{2},0,-\sqrt{2},0$$

zarkon · Answer

yes...if you wrote your equation as 

$$y=5x^2-10$$

then the x-intercepts would be $$(\sqrt{2},0),(-\sqrt{2},0)$$

anonymous · Answer

so i need the parenthesis for them thats why i was getting it wrong?

zarkon · Answer

prob
they are points

anonymous · Answer

yep that was the issue lol

zarkon · Answer

ah