Question

what is the equation of the line that is passes through the origin and parallel to the line 5x-3x+2=0?

Answer 1

passes through origin so constant is zero, next parallel to that line, so find the slope!

Answer 2

oh.. sorry it's 5x-3y+2=0..

Answer 3

i really need a solution for this problem.. :)

Answer 4

@kris100 as mashy said find the slope is m=y2-y1/x2-x1 is the formula?

Answer 5

@ nudnick.. is that you doms?

Answer 6

estudier answered you nudnick : "For ax+by = c, slope is -a/b"

Answer 7

@mashy after solving for the slope what is next?

Answer 8

@nudnick i just solve for the slope.. what should i do next? have you figured it out?

Answer 9

@kris i am not doms

Answer 10

@kris i am not sure about it.....this is what i got y=5x/3 please check. i used the solution for a parallel line...

Answer 11

Once u have the slope use

y = m(x-a) +b for slope m and point (a,b)

Answer 12

@estudier then what solve for parallel line?

Answer 13

I just answer u. Parallel lines have same slope.

Once u have the slope use y = m(x-a) +b for slope m and point (a,b)

Origin is (0,0), right?

Answer 14

if your line pass through the origin, the equation is y = mx, which means if you have found the slope, you've got the solution

Answer 15

let the line be y=mx
since lines are parallel,slopes are equal
m=(-b/a)
m=-5/-3
=5/3
the line is hence y=(5/3)x
5x-3y=0