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Can someone explain to me why this function is continuous: g(x) = square root of 49 - x^2 on the interval (-7,7)
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x^2 takes values from 0 till 49 on the above interval So 49-x^2 takes values of 49 to 0 on the same interval You have to take the square root of positive numbers, that does not cause a problem so the function is continuous.
Since the limits of the function g(x), from the left and from the right, are equal to the value of the function at the points x = -7 and x = 7
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