how to solve x^2+kx-19
it's not an equation, it can't be solve... maybe a "=0" is missing ?
im suposee to find the value of k
yeah but you should have an "= something"
since c=sqrt(k/2) id start with that :)
i assume it wants you to solve for k such that it is a complete square?
c=(k/2)^2 that is
had a synapse crossed lol
i don't understand... what is c here ?
ax^2 +bx + c is the usual generic format for a quad
a complete square is then the case where c = (b/2)^2
yeah, but c = 19... ?
yep
so you decide it's a complete square, and then you resolve the thing ?
thats my assumption; i could be wrong since the information in the problem is open to interpretation :)
okay, i understand know. i absolutely didn't know that thing of "complete square". must not being teached by french teachers.
.... well, you cant blame them to much .. they are french :)
hey, i'm french too :p
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