How many we can arrange the word SESI? How many we can arrange the word SESE? How many we can arrange the word SERI?
24 ways
There are three different questions so there should be three different answers.
in the first case, you have 4 letters you are rearranging, so thats 4! = 24, but two of the letters are the same. So you divide by 2! = 2 So you final answer is 24/2 = 12.
That should tell you how to do the rest. Its always going to be 4!, but you divide if any of the letters are repeated.
3 different questions which all rely on the same logic to solve ...
the process is more important than the answers :)
when we have multiple terms that are identical; the formula is: \[\frac{n!}{n_1!n_2!n_3!...n_k!}\] if i recall correctly
right right :)
How many we can arrange the word SESI? For this question 72 is the answer..
(4!/2!) * 6
Can anyone explain this answer?
There arent even 72 ways to arrange 4 things, there are 4! = 24. No way the answer can be bigger than 24.
where did that times 6 come from?
4!/2! is the ways of arranging SESI .but among them we also need to arrange. Taking SS as one and E and I as other two.Among themselves we can arrange in 3! ways. Thus total no of ways (4!/2!) * 3!
\begin{array}c &&s&i&-sesi\\ &e\\ &&i&s&-seis\\ &&e&i&-ssei\\ s&s\\ &&i&e&-ssie\\ &&e&s&-sies\\ &i\\ &&s&e&-sise\\ &&s&i\\ &s\\ &&i&s\\ &&s&i\\ e&s\\ &&i&s\\ &&s&s\\ &i\\ &&s&s\\ &&e&i\\ &s\\ &&i&e\\ &&s&i\\ s&e\\ &&i&s\\ &&s&e\\ &i\\ &&e&s\\ &&s&e\\ &s\\ &&e&s\\ &&s&s\\ i&e\\ &&s&s\\ &&e&s\\ &s\\ &&s&e\\ \end{array} etc...
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