Question

i am trying to integrate

Answer 1

I am writing it now

Answer 2

\[\int\limits_{}^{} (3\sec^2t)/(6+3tant) dt\]

Answer 3

can me move something out as a constant?

Answer 4

You can factor out a 3.

Answer 5

only the 3 right?

Answer 6

the 6+3 on the bottom stays right?

Answer 7

i integrated and got the right answer but there is a constant 3 still left

Answer 8

factor a 3 out of the top and bottom perhaps ...

Answer 9

so would i be left with 2+1 on the bottom??

Answer 10

the top looks to be a derivative of the bottom if i see it right

Answer 11

hmm so its in that form du/u

Answer 12

6 + 3tan(t) derives to

0 + 3sec^2 right?

Answer 13

so take that bottom as u

Answer 14

that is of the form du/u if im right :)

Answer 15

thanks

Answer 16

youre welcome :)