You roll 2 dice. What is the probability that the sum of the dice is odd or 1 die shows a 5?
count.
you get lots.
for the odd it would b 3/6 1/6
(5,1) (5,2)(5,3) 5,4) (5,5) (5,6) (1,5)(2,5)(3,5)(4,5)(6,5) (1,2) (1,4) (1,6) (2,1) (2,3) (3,2) (2,4) (3,6) (4,1) (4,3) (61) (6,3) first row is all of the first condition next rows are all that give a total of odd not recounting what is in first row
check that i didn't miss any but i get \[\frac{23}{36}\]
you can use some sort of formula but with dice easier to count
Isn't it asking about rolling two dice together one time?
i think so
OK, I missred your earlier post.
yes i take it to mean that. i listed all the ordered pairs that fit your description and i could 23 of them.
@skittles the probability that you get an odd number is 1/2 but the probability that ONE die shows at 5 is not 1/6. that is the probability that the first die (or second) shows a 5.
so how do i get the finmal answer?
amistre, think u can help? long time no c :P
You roll 2 dice. What is the probability that the sum of the dice is odd or 1 die shows a 5 1 2 3 4 5 6 1 x x x x 2 x x x 3 x x x x 4 x x x 5 x x x x x x 6 x x x might have gotten them all
count the xs and put it over 36
23/36
thats what I get also if i did it right ;)
That's what I got, too.
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