Question

4x^2-1 Factor

Answer 1

15x maybe?

Answer 2

divide both sides by 4
simplifes to x^2-1/4=0
(x+1/2)(x-1/2)-0
x=1/2 and x=-1/2

Answer 3

this is a difference of two squares:
\[a^2-b^2 = (a+b)(a-b)\]
we can rewrite your problem as:
\[4x^2-1 \Rightarrow (2x)^2-1^2\]
so in this case:
\[a = 2x, b = 1\]

Answer 4

Made an incorrect assumption - Joe is correct if it is not equal to zero.

Answer 5

thanks guys