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Solve EXACTLY in terms of log. 10/(1+10^-x) = 2 x= ?
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\[\frac{10}{1+10^{-x}} =2\]\[\implies 10 = 2(1+10^{-x})\] Can you solve from here?
10= 2(1+1/10x) ?
That's a good start, though it's 10^x not 10x
been a while so thanks for the patience
ah so 1/10^x
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So: \[10 = 2(1+\frac{1}{10^x})\]
Now distribute the 2 to each term in parens.
10= 2+2/10^x ?
so 10= 2 + 1/8^x ?
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