Question

Solve exactly.
log(base 6)(x+1) + log(base 6)(x+2) = 1

x= ?

Answer 1

I though it would work out to (x+1) = 1-(x+2)

Answer 2

based on what you had told me earlier

Answer 3

no this is a different situation.

Answer 4

You need to use properties of logarithms in this one.

Answer 5

no first combine into 1 log

Answer 6

When you have a sum of logs, you can make it into the log of a product:

\[log_ba + log_bc = log_b(a\cdot c)\]

Answer 7

log_6(x+1)(x+2) = 1
(x+1)(x+2) = 6
...

Answer 8

x^2+3x+2=6

Answer 9

Right, then solve the quadratic.

Answer 10

subtract 6 and equal to 0?

Answer 11

Yep

Answer 12

x^2+3x-4=0 so (x+4)(x-1)

Answer 13

perfect

Answer 14

and a log cannot be negative correct? so x=1 ?

Answer 15

yes

Answer 16

awesome you two have been huge helps

Answer 17

np