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Solve exactly log (base 3)(2x-3) = 0 x= ?
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Good to see you again jahtoday
I saw your post on my other question and felt very stupid lol
\[log_b(a) = 0 \implies a = b^0 = 1\]
So how does that apply to your problem here?
2x-3=3^0 ?
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lol sry just trying to point in the right direction and yes thatsright
Correct.
And 3^0 = 1
so 2x-3=1 then 2x=4 so x=2?
yup
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Nicely done.
awesome thank you both
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