A druggist has two mixtures of a certain chemical and water, one containing 10% of the chemical and the other containing 40% of the chemical. How much of each mixture should he use to make 10 ounces that contain 25% of the chemical?
i got 0.5?

Question

saifoo.khan · Answer

u should get 2.5

anonymous · Answer

i though the answer was 5

saifoo.khan · Answer

nope!

anonymous · Answer

well heres what i did
x=amount of 10% solution used
10x+40(10-x)=25(10)
x+4(10-x)=25(1)
x+40-4x=25
3x=15
so x=5

saifoo.khan · Answer

.10X+.40(10-X)=.25*10
.10X+4-.4X=2.5
.3X=2.5-4
.3X=1.5
X=1.5/.3
X=5 OZ. OF EACH MIXTURE IS NEEDED.
PROOF:
.10*5+.40*5=2.5
.5+2=2.5
2.5=2.5

anonymous · Answer

the question asks how much of each mixture and that is what x stands for so the answer would be 5, no?