Question

2x^2=6 solve and find the x intercepts of 2x^2-6

Answer 1

so we are solving:
\[2x^2-6 = 0\]
First thing we can do is factor out a 2 from both terms:
\[2x^2-6=0 \Rightarrow 2(x^2-3) = 0\]

Answer 2

Dividing by that 2 just leaves us with:
\[x^2-3 = 0 \Rightarrow x^2 = 3 \Rightarrow x = \pm \sqrt{3}\]
That would be the x -intercepts.

Answer 3

sqrt of 3?

Answer 4

OK I see how you did it

Answer 5

plus or minus the square root of 3.