AJ wanted to get a photo enlarged so that the length and width of the enlargement would be twice those of the original. Because the original was 40 cents, AJ assumed the enlargement would cost 80 cents. Does this seem reasonable? I dont get this question.
basically the information they are assuming that you will guess (retardedly on their part) is that the cost of something depends on the area printed. so the question is simply asking if you double the length and the width of an item, does the area double as well?
to look at this lets just do a case study, lets assume instead of money, the 40cents is area. so lets decide arbitrarily that this picture is 8x5 since 8 times 5 is 40. (you can choose anything here, this is just an example) so lets double both the sides and see if we can get 80 out of it. by doubling the sides, we get a picture that is 16x10. taking the area of this (length times width) we get that it is 160 inches^2 so instead of doubling the area, we quadrupled it, which in this case, is also quadrupling the cost.
so his assumption that doubling the length and width would double the cost is false.
WOW!!!!!!!! THANK YOU SO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! :)
no prob! i hope i explained it in a way you could understand, if not let me know and i'll see if i can do better!
No no, you explained it in the best way!!!! :D
i'm glad!! good luck with the homework!
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