Question

Factor completely 11s^2+392st+343t2

Answer 1

i dont know but you could use the quadratic equation

-b+or- sq.rt. of(b^2-4ac)
all divided by 2a

Answer 2

use a=343s, b=392s,c=11s
t=[-b+- sq.rt(b^2-4ac)]/2a
t=[-(392s)-+sqrt((-302s)^2 -4(343)(11s))]/2(343)
t=[-(392s)-+sqrt((153664s^2-15092s^2)]/(686)
t=[-392s-+sqrt(138572s^2)]/686
t=[-392s-+(14sqrt707)s]/686
t=[-392s-+372.25]/686
+... t=-285.64s/686 =-0.4163879s ans
- ... t=-498.35788s/686=-0.726469s ans

Answer 3

11s^2+392st+343t^2
=(t+0.726469s)(t-0.4163879s )
=(t-285.64s/686)(t-498.35788s/686)
=((686t-285.64s)/686))((686t-498.35788s)/686) ans..