Question

Suppose that y depends on x, and x^3-2xy+y^3=1.The derivative dy/dx is given by ?

Answer 1

3x^2-2dy/dx+3y^2dy/dx=0

Answer 2

Now solve

Answer 3

dy/dx=(-3x^2)/(-2+3y^2)

Answer 4

Thanks!

Answer 5

\[3x^2-2\left(y+x\frac{dy}{dx}\right)+3y^2\frac{dy}{dx}=0\]

Answer 6

now solve for dy/dx

Answer 7

yea got it.Thanks!

Answer 8

as long as you know the 'answers' above are not correct

Answer 9

yeaps.i tried.and got the answer in one of the choices given.Thanks a lot btw!!

Answer 10

ok