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Determine the dimensions of the largest rectangle that can fit inside of the ellipse (x^2/4)+(y^2/16)=1
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im getting: \[2\sqrt{2} \] for the width and \[4\sqrt{2}\] for the height. i can scan my work and post if needed,
that would be nice, i just need to see how its done, and hopefully i can figure it out from there
you took the derivative of the area of the rectangle to maximize correct o.0?
also, couldve you hav solved for x instead of y and work the problem for there o.0?
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