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What is the equation of a line that passes through (7, -2) and has a slope of 3?
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yo
Use point-slope form. \[y - y_1 = m(x - x_1)\] m = 3 (x1, y1) = (7, -2)
which "equation" of the line is appropriate?
first plug in the slope to your point-slope equation to get: y=3x+b now put in your point for x and y and solve for b -2=21+b b=-23 so your equation is: y=3x-23
i mean slope-intercept
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I like the: y = mx -mPx +Py version :)
y = 3x -3(7) -2
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