Find the volume of the solid formed when the region described is revolved about the x-axis using disk method

the region under the curve y=sqrt[3]{x} on the interval 0le x le 8

Question

Find the volume of the solid formed when the region described is revolved about the x-axis using disk method

the region under the curve y=sqrt[3]{x} on the interval 0le x le 8

amistre64 · Answer

since there is only one curve to contend with; it makes life easier

amistre64 · Answer

the radius of each little circle we form is simply f(x)

so integrate from 0 to 8; pi [cbrt(x)]^2 right?

amistre64 · Answer

$$\int_{0}^{8} pi(\sqrt[3]{x})^2dx$$

anonymous · Answer

ya.

anonymous · Answer

hey, I know the correct way. I do wrongly with integrate.Thanks.

amistre64 · Answer

the trick here might be to convert the radical into its exponent form :)

anonymous · Answer

I do it wrongly at 1st, when I integrade, I divide wrongly, so I get the wrong answer.