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Find the particular solution for the anti-derivative of f'(x) = 2x^3 + 1 – sin x, if f(0) = 1.
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Take integral
That doesn't help my confusion... :(
Do you know how to take integral
No
Can you teach me?
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Integration is a broad subject but here is the basic integration technique \[\int{ax^b}=\frac{a}{b+1}x^{b+1}\]
Left out dx above \[\int{ax^b dx}=\frac{a}{b+1}x^{b+1}\]
okay. still confuseddd
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