Question

please help me guys = ]!!!
Given two spheres, if the volume of the first sphere is 4/3*3.14 and the volume of the second sphere is 36*3.14 , which is the relation of the second radius to the first?
squared
tripled
doubled
multiplied by a factor of 8/3

Answer 1

First lets find out how many times the volume grew. We will divide the second sphere's volume by the first sphere:
\[\frac{36*\pi}{\frac{4}{3}*\pi}\]
This comes out to be 27 (i think, might want to plug that in a calculator.)
So the volume grew by a factor of 27, but thats in cubic units (volume is measured in cubic units). A radius is just regular units, so we cube root 27 to get out real answer:
\[\sqrt[3]{27} = \sqrt[3]{3^3} = 3\]
So tripled is the answer.

Answer 2

thanks hun you helped me when no one could!