Question

Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
P2 = P1 + 4w
P2 = 2P1 + w
P2 = 2P1 + 4w
P2 = P1 + w

Answer 1

p2=2L+4w

Answer 2

mark o. you mean P2 = 2P1 + 4w

Answer 3

oh, i didnt noticed its pi,,lol..hold on ..ill fig it out a sec..lol

Answer 4

yes its p2=2p1+4w ans

Answer 5

Calculate the volume of a sphere where the radius is 9 meters.

Answer 6

heres the sol. PERIMETER P=2L+2W
L1=L, W1=W...P1=2L+2W
L2=2L, W2=4W....P2=2(2L)+2(4W)
P2=4L+8W
SO P2=2P1+4W
P2=2(2L+2W)+4W=4L+4W+4W=4L+8W ANS..

Answer 7

what is it in cubic meters

Answer 8

????

Answer 9

Calculate the volume of a sphere where the radius is 9 meters.
VOLUME OF SPHERE V=(4/3)PI*R^3
V=(4/3)PI*(9)^3=972PI ANS..

Answer 10

V=972PI CU.METER =972*3.14=3053.63 M^3

Answer 11

did you understand the solution how to get it? any question?