Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
P2 = P1 + 4w
P2 = 2P1 + w
P2 = 2P1 + 4w
P2 = P1 + w

Question

anonymous · Answer

p2=2L+4w

anonymous · Answer

mark o. you mean P2 = 2P1 + 4w

anonymous · Answer

oh, i didnt noticed its pi,,lol..hold on  ..ill fig it out a sec..lol

anonymous · Answer

yes its p2=2p1+4w  ans

anonymous · Answer

Calculate the volume of a sphere where the radius is 9 meters.

anonymous · Answer

heres the sol. PERIMETER P=2L+2W
L1=L, W1=W...P1=2L+2W
L2=2L, W2=4W....P2=2(2L)+2(4W)
                           P2=4L+8W
SO P2=2P1+4W
     P2=2(2L+2W)+4W=4L+4W+4W=4L+8W ANS..

anonymous · Answer

what is it in cubic meters

anonymous · Answer

????

anonymous · Answer

Calculate the volume of a sphere where the radius is 9 meters.
VOLUME OF SPHERE V=(4/3)PI*R^3
                             V=(4/3)PI*(9)^3=972PI  ANS..

anonymous · Answer

V=972PI CU.METER =972*3.14=3053.63 M^3

anonymous · Answer

did you understand the solution how to get it? any question?