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Mathematics 22 Online
OpenStudy (anonymous):

Evaluate C(n, n).

OpenStudy (anonymous):

define C

OpenStudy (anonymous):

There was nothing for C. Thats what confused me. I thought there had to be something for C?

OpenStudy (anonymous):

C can mean a lot of different things. Is this C for combinatorics?

OpenStudy (anonymous):

it stands for combination my choices are 0, 1, and n

OpenStudy (anonymous):

Ok, well then: \[C(n,r) = \frac{n!}{r!(n-r)!}\] So if you plug in n for r, and n for n, what do you get?

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