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If → u = 3/5 →i - 4/5→j, find D→u f (2, pi/3) DESPERATE!!
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problem 1 part b
It want directional derivative
\[ f(x, y) = x cos y \] let's find Gradient \[\nabla f=<cos (y),-xsin (y)>\] In the direction of \[\frac{3}{5}i-\frac{4}{5}j\] This is the unit vector since magnitude is 1 Now take dot product \[<3/5,-4/5>.<cos (y),-xsin (y)>\] \[\frac{4}{5} x \sin (y)+\frac{3 \cos (y)}{5}\] Plug in value (x,y) --> (2,pi/3) \[\frac{3}{10}+\frac{4 \sqrt{3}}{5}\]
that's all??
yes
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oh wow! Thank you!!!! have been stuck on this problem for 2 days I was thrown off the the D vector u
u r a life saver!
wow, you've asked this question like how many times? glad I could help
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