Question

help me with this.....
find the point on the curve y=x^3 + x^2 - x +1 where the tangent is horizontal....

Answer 1

it is the point where dy/dx =0

Answer 2

im not sure..i'm blank now:((

Answer 3

the tangent is horizontal when dy/dx = 0
dy/dx = 3x^2 + 2x - 1 = 0
x = 1/3 or -1

Answer 4

owh...then y we find by subtitute x with 0??is it??

Answer 5

no.

Answer 6

i got (1/3,16/27) and (-1/0)

Answer 7

wrong. substitute x = -1. do it properly this time.