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Mathematics 19 Online
OpenStudy (anonymous):

Please help! A sculpture was purchased for $4,000. The value of the sculpture increases at a rate of 4% per year. After 10 years the sculpture will be worth $5,920.97. In how many years wil the sculpture be worth $10,000? Round to the nearest tenth of the year.

OpenStudy (anonymous):

if it is really 10% per year then all you need is to solve \[10000=4000(1.04)^y\] for y

OpenStudy (anonymous):

you can solve exactly via \[2.5=(1.04)^y\] \[y=\frac{\ln(2.5)}{\ln(1.04)}\]

OpenStudy (anonymous):

sorry i meant to say "if it is really 4% per year"

OpenStudy (anonymous):

2.403?

OpenStudy (anonymous):

i get 23.36

OpenStudy (anonymous):

you have to type it in carefully.

OpenStudy (anonymous):

make sure to closes parentheses or else it will mess up.

OpenStudy (anonymous):

Oh I see. So it will take 23.36 years until the sculpture will be worth $10,000?

OpenStudy (anonymous):

that is what i got, yes

OpenStudy (anonymous):

rounded gives 23

OpenStudy (anonymous):

Thank you so much satellite73! :)

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