Question

may I have an answer please? Question attached.

Answer 1

Same way we did it before, this is a differece of cubes this time. Use the fact that: a^3-b^3=(a-b)(a^2+ab+b^2) They already gave you (a-b), its (3y^5-4z).
a=3y^5 and b=4z

Answer 2

I just don't know how to make the problem like that. :/

Answer 3

They gave you the binomal (a-b).I told what a and b represent. Now in the trinomial (a^2+ab+b^2), just plug in those values for a and b

Answer 4

So ignore the a-b, just use the numbers that are there for the rest of the problem?

Answer 5

((3y^5)^2+(3y^5)(4z)+4z^2)?

Answer 6

well, dont ignore (a-b), cause its part of the over facotrization.But defiently use the fact that they ahve already said what a and b are. That way you can finish the second part of the factored form (a^2+ab+b^2)

Answer 7

right exactly you got, now simplify it using the exponent rule

Answer 8

9y^10+12y^5z+4z^2

Answer 9

nice

Answer 10

Thanks :)

Answer 11

It told me the answer is incorrect.

Answer 12

hold on the last term, is suppose to be 16z^2

Answer 13

Ahh, that's why.