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Another logarithm. log[5](x+116)=4-log[5](x-4)
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Move all your logs to the same side, and combine them by the property that: \[log_b(a) + log_b(c) = log_b(a\cdot c))\]
I'm confused by the negative in front of the second log
Just add \(log_5(x-4)\) to both sides of the equal sign.
That will zero out the one on the right, and make a new, positive one on the left you can combine.
log[5](x+116/x-4)=4 and solve from there??
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Not divide, multiply.
\[log_5((x+116)(x-4)) = 4\]
(x+116)(x-4)=5^4 and go from there?
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