I need help please! Can anyone break this down for me by showing all the work. Perform the indicated operation:
21x^5-56x^4+28x^8/7x^4

Question

anonymous · Answer

$$21x^5-56x^4+28x^8/7x^4  \rightarrow 21x^5-56x^4+28x^4/7$$
$$\rightarrow  21x^5-56x^4+4x^4  \rightarrow   21x^5-52x^4$$

factorising gives;
$$x^4 (21 x-52)$$

Enjoy

anonymous · Answer

I think the 7x^4 is supposed to be divided into everything

anonymous · Answer

yes......

anonymous · Answer

(21x^5-56x^4+28x^8)/(7x^4)

anonymous · Answer

So just do 1 at a time, first one is

21x^5/7x^4   u do 7 into 21 and subtract the bottom from top exponents

=3x