Question

I need help please! Can anyone break this down for me by showing all the work. Perform the indicated operation:
21x^5-56x^4+28x^8/7x^4

Answer 1

\[21x^5-56x^4+28x^8/7x^4 \rightarrow 21x^5-56x^4+28x^4/7\]
\[\rightarrow 21x^5-56x^4+4x^4 \rightarrow 21x^5-52x^4\]

factorising gives;
\[x^4 (21 x-52)\]

Enjoy

Answer 2

I think the 7x^4 is supposed to be divided into everything

Answer 3

yes......

Answer 4

(21x^5-56x^4+28x^8)/(7x^4)

Answer 5

So just do 1 at a time, first one is

21x^5/7x^4 u do 7 into 21 and subtract the bottom from top exponents

=3x