Solve the system of equations using the substitution method. Enter the answer as an ordered pair. 3x - y = 3 y = 2x + 2
-1, 0
3x - (2x +2) = 3, now you continue...
y= -3x +y
3x-(2x-2)=3 3x-2x-2=3 x-2=3 x=5 i think...my brain is kinda fryed from all the math lol
substitution= get the equation in the term of one variable, and then plug that into the second equation. ex. a+b=1, and a*b=0 Get the 1st equation in terms of a (or b) a=1-b plug that in wherever u see a in the second equation. (1-b)*b=1
For this one, I'd get the 1st equation in terms of y 3x-y=3 -y=3-3x y=-3+3x
x = 5 y = 12
as an ordered pair that would (5,12)
Now plug that in wherever u see y in the second equation. -3+3x=2x+2 x=5
Now that u know x=5, go back to one of the original equations, plug in a 5 wherever u see x, and solve for y
y=2(5)+2 y=10+2 y=12
many answers r suitable for this questions
So x=5, y=12.
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