Question

5/(x-4) + 3/(x+4) = -6x/(x^2-16)
solve for x

Answer 1

-0.5714

Answer 2

factor first. x^2-16 is the difference of 2 perfect squares, so (x-4)(x+4)

Answer 3

. vijay that says wrong

Answer 4

cannot be

Answer 5

If u multiply the whole equation by (x-4)(x+4), all ur denominators go away

Answer 6

that's what it says

Answer 7

maybe no negative?

Answer 8

x = -4/ 7

Answer 9

5(x+4)+3(x-4)=6x

Answer 10

-4/7 = -0.5714

Answer 11

5x+20+3x-12=6x

Answer 12

it is -4/7

Answer 13

Move the RHS to the LHS\[\frac{6 x}{x^2-16}+\frac{5}{x-4}+\frac{3}{x+4}=0 \]Combine fractions and simplify.\[\frac{2 (7 x+4)}{(x-4) (x+4)}=0 \]