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Mathematics 21 Online
OpenStudy (unknown):

what is the factorization of the polynomial below? x^3+2x^2-35x

OpenStudy (zarkon):

\[x(x+7)(x-5)\]

OpenStudy (anonymous):

Zarkon is beast!

OpenStudy (anonymous):

Factor out x: x(x^2+2x-35) Then factor the quatratic: x(x-5)(x+7)

OpenStudy (unknown):

3x^2+30x+48

OpenStudy (unknown):

.. any takers

OpenStudy (anonymous):

3(x+2)(x+8)

OpenStudy (unknown):

-x^2-15x-54

OpenStudy (anonymous):

Learn how to do it for yourself.

OpenStudy (unknown):

im in 6th grade give me some slack

OpenStudy (anonymous):

I was doing this in 3rd. This place is not for people to answer every problem for you, rather to help you understand things you do not.

OpenStudy (zarkon):

use WolframAlpha

OpenStudy (anonymous):

Make clear what you do not understand, and you will be aided.

OpenStudy (anonymous):

Or WolframAlpha, if you have no interest in actually learning anything for yourself, anyway.

OpenStudy (unknown):

i wanna learn how to do it on my own. can you guide me step by step on this next problem

OpenStudy (unknown):

8x^2+10x-25

OpenStudy (unknown):

i just don't understand how to factor when there is no gcf and there is a bigger number in front.

OpenStudy (anonymous):

First, factor out the 8. Then, try to find two numbers m and l so that: m+l=the coefficient of the middle term and ml is equal to the constant term. If that doesn't yield an obvious solution, look up a technique called 'completing the square,' and ask if you have any questions.

OpenStudy (unknown):

okay so the factors of 8 are 1 & 8 and 2&4.

OpenStudy (anonymous):

No, factor out the 8, as in: 8(x^2+(5/4)x-(25/8))

OpenStudy (unknown):

whatt. *8x^2+

OpenStudy (anonymous):

What's the problem?

OpenStudy (unknown):

8x^2+10x-25

OpenStudy (unknown):

ohh

OpenStudy (unknown):

uhmm i'm not comprehending what the (5/4)x-(25/8))

OpenStudy (anonymous):

What happens when you divide 10x and -25 by 8?

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