Question

find the center of the circle
x^2+y^2-8x-2y=19

Answer 1

don't let me post answer

Answer 2

\[x^2-8x+y^2-2y=19\]

Answer 3

\[(x-4)^2+(y-1)^2=19+16+1\]

Answer 4

\[(x-4)^2+(y-1)^2=36\]

Answer 5

division both side by 36 you get \[\frac{(x-4)^2}{36}+\frac{(y-1)^2}{36}=1\]

Answer 6

the center: ( 4,1)

Answer 7

Wow. Thank you!

Answer 8

uewc