Question

Find the Maclaurin Series as far as the fourth term for the following equation:
cos^2 2x

Answer 1

f(x) = f(0) + f'(0)x + f''(0)/2! x^2 +.....
= cos^2 2)0) + d(cos^2 2x) dx *x +..
sorry gotta go

Answer 2

d(cos^2 2x) dx *x = -4 sin^2 2x*x

Answer 3

= -4x sin^2 2x
- sorry i have to go

Answer 4

okay... im just trying to understand what you've done. I think i've got my head around it

Answer 5

http://www.wolframalpha.com/input/?i=Taylor+Cos^2+%282x%29

Better check it.....

Answer 6

but thats taylor series

Answer 7

Taylor about 0 = MacLaurin

Answer 8

so thats the correct answer

Answer 9

Wolfram says it is, do it manually if u don't believe it...