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the ave. of X numbers is 5. If Y is added to each number, the ave. will be?
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Hi moongazer, Average is sum/number, if you increase sum by 5y and divide by 5, then average is 5+y.
\[\sum_{i}^{X}/X =5\] adding y \[\sum_{i}^{X}/X +y =5+y\] hence average = 5 +y
waT?
where did you get 5y?
5 numbers, 5 y's.
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you are correct but i can't understand how this works
You added a y to each number and there are 5 numbers so 5y.
could you give example?
Example of what?
1+2+3 = 6, 1+y +2 +y +3 +y = 6 +3y
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ohh ok thanks
how did you get 5+y?
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