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If the temperature of a gas is increased from 20 degrees C to 40 degrees C, by what factor does the speed of the molecules increase?
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The temperature of a gas is proportional to the square of the speed of the molecules within it, since Temperature is just the average of the kinetic energy of the molecules of the gas. The increase in Temperature (converting to kelvin) is 313/293 = 1.4695 times. Hence the speed will increase by a factor of (\sqrt{1.4695}=1.212\) times.
Thank-you very much. I understand now :D
The catch is not to use C but K. 2 times bigger C does not keen 2 times more heat
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