Question

Help please? Solve:

(RESPONSE)

Answer 1

\[\log_{4}3x+\log_{4}2=\log_{4}24\]

Answer 2

when you add logarithms of the same base, you can simplify those terms by combining their arguments to get:\[\log_{4} 3x+\log_{4}2 = \log_{4}6x \]now you can solve 6x =24

so x=4

Answer 3

Thanks nothingmaster! :)

Answer 4

No problem!

To make that clear, when you add logs with the same base, you multiply the arguments together, when you subtract them you divide.