Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

I really need a correct answer please. suppose f(x)=x^2+2 so find the graph of f(2/3x). I will attach 4 graphs to choose a correct answer from, thank you.

OpenStudy (anonymous):

OpenStudy (anonymous):

Are you sure that's supposed to be f(2/3x)? I don't think it makes sense to have an "x" in the argument...

OpenStudy (anonymous):

Yes, I promise.

OpenStudy (bahrom7893):

no I think I know what he means

OpenStudy (anonymous):

maybe f(2/3)?

OpenStudy (anonymous):

It confuses me soo much

OpenStudy (bahrom7893):

is it (2/3)x or 2/(3x) ?

OpenStudy (anonymous):

sceenshot

OpenStudy (anonymous):

screen*

OpenStudy (bahrom7893):

Okay good: f(x)=x^2+2 f((2/3)x)=(2/3)^2x^2+2

OpenStudy (bahrom7893):

So graph this: y = 4x^2/9 + 2

OpenStudy (anonymous):

Ok hang on

OpenStudy (anonymous):

that looks like the first graph. Is that correct?

OpenStudy (anonymous):

because 1 and 2 are alike, just ones wider than the other

OpenStudy (bahrom7893):

I don't really know I don't have a calculator, you can check by plotting x=0 and seeing what y is to get a more exact idea..

OpenStudy (anonymous):

thank you :3 graph one was correct :)

OpenStudy (bahrom7893):

Okay np =)

OpenStudy (anonymous):

Plot 1.jpg is the answer. Refer to the attachment.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
4 hours ago 3 Replies 0 Medals
Arriyanalol: help
4 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
7 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
7 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!