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an airplane is flying E40degreesN at a speed of 600km/h. the wind is blowing at 10km/h in direction N20degreesW. determine the resultant velocity of the plane
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This is a vector addition problem. Find the x and y components of the velocity of the airplane flying E40degreesN at a speed of 600km/h. The result is a vector in x and y. Then do the same for the wind speed and direction. The velocity is the sum of those two vectors. If you need the speed, you can find it by finding the magnitude of the resulting vector. x1 = 600 Cos(40) = 459.63 y1 = 600 Sin(40) = 385.67 x2 = 10 Cos(110) = -3.42 y2 = 10 Sin(110) = 9.39 So Va = <459.63-3.42,385.67+9.39> Where Va is the resultant velocity of the airplane
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