find the factorization of the polynomial below. Enter each factor as a polynomial in descending order. 3x^2 + 7x + 2 This one confuses me.
(3x+1)(x+2)
Why is that though? I thought you had to make it equal to 7? or does it not matter?
3x*2+x*1=6x+x=7x
jahtoday is quite correct.. and you can check by using the FOIL method to multiply it out (3x+1)(x+2)=3x^2+7x+2
Yes kenzie, using his numbers, they do add up to 7x
if you have ax^2+bx+c, then all you have to do is find the factors of a*c that have product a*c and that add up to be b. a=3, b=7, c=2 a*c=3*2=6*1 b=7=6+1 so replace the bx=7x with 6x+1x 3x^2+7x+2 3x^2+6x+1x+2 and then factor by grouping 3x(x+2)+1(x+2) (x+2)(3x+1)
It's tricky because this one adds a co-efficient to x^2 you'll have to pay mind to
Which of the following polynomials does not have real roots? A.12x2 - 17x - 7 B.x4 + 5x2 + 6 C.2x4 + 13x3 + 21x2 D.x2 + x - 2
A
How many roots does y = x2 - 6x + 9 have? It may help to graph the equation
x^2
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