Ask
your own question, for FREE!
Mathematics
8 Online
Help me solve this exponential equation plz!! 256^(5x)=64^(x+4)
Still Need Help?
Join the QuestionCove community and study together with friends!
4^4=256 and 4^3=64 so 256^(5x)=4^(4*5x) and 64^(x+4)=4^(3*(x+4)) u can substitue and solve from there
2^8^(5x) = 2^6^(x+4) 40x=6x+24 34x=24 x=12/17
I guess 4 would have been easier 20x=3x+12 17x=12 x=12/17 :)
lol
it would still come out to 12/17 either method correct?
Still Need Help?
Join the QuestionCove community and study together with friends!
yup as mrjoselson's steps showed. 4 would just be faster
Thank you both =)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
17 hours ago
1 Reply
0 Medals
5 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
3 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal