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OpenStudy (anonymous):
just need someone to confirm my answers....use substitution e^(x)=u to valuate the integral e^(x)/(1+e^(x)) dx
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OpenStudy (anonymous):
So du=e^x dx
\[\int\limits \frac{du}{1+u}\]
Let s=1+u
ds=du
\[\int\limits \frac{ds}{s}=\ln|s|+C \rightarrow \ln|u+1|+C \rightarrow \ln|e^x+1|+C\]
myininaya (myininaya):
\[\int\limits_{}^{}\frac{du}{u}, with u=e^x+1 => du=e^x dx\]
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
\[withu\]
myininaya (myininaya):
i wonder why they want you to use u=e^x not u=e^x+1
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OpenStudy (anonymous):
It said let u=e^x thats why I did it that way.
myininaya (myininaya):
i know male
OpenStudy (anonymous):
cant make a difference can it? since 1 is a number i mean
myininaya (myininaya):
i just don't know why they would ask you to use that substitution
OpenStudy (anonymous):
ya that's the problem says it's supposed to be. this teacher likes to give hard to impossible problems tho so i figured i'd double check
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myininaya (myininaya):
i mean its okay but i like mine more
OpenStudy (anonymous):
you better hurry before saifoo becomes a sensei
myininaya (myininaya):
hey satellite what number of medals do i need to get to sensei level?
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