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find the shared area between curves y=2 sin(x), y=e^(4 x), x=0, x=pi/2
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i would first make a rough picture of the graph of both functions together and would look for the top function and the bottom function and do \[\int\limits_{0}^{\frac{\pi}{2}}( Top-Bottom)dx\]
thats what i did
ok give me just a sec and i will do it for you and scan
so it is obvious e^(4x) is above 2sin(x) lol
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so we have \[\frac{1}{4}e^{\frac{\pi}{2}}-\frac{1}{4}-2=\frac{1}{4}e^\frac{\pi}{2}-\frac{1}{4}-\frac{8}{4}\] \[=\frac{1}{4}e^\frac{\pi}{2}-\frac{9}{4}\]
is that what you got?
i;m gonna watch tv now
thanks, but you missed one number, it not pi/2, its 2pi
yea you are right it should be 1/4*e^(2pi)-9/4
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