Question

find the area between y=x/(x^(2)+1), the x axis, x=1 and x=10

Answer 1

jst do intgration

Answer 2

342 is ans

Answer 3

ya its integration, but i don't understand the x axis part. is it y=0 or something?

Answer 4

1.96 is the correct ans my mistake

Answer 5

\[\int_{1}^{10}\frac{x}{x^2+1}dx\]



let \[u=x^2+1\]

Answer 6

so does the x axis part not really matter? it's just a boundary line and i just need to use the x=10- and x=1?

Answer 7

integration with dx itself means it is with x axis

Answer 8

you could also write it like this

\[\int_{1}^{10}\left(\frac{x}{x^2+1}-0\right)dx\]

Answer 9

\[\int_{a}^{b}\left(top-bottom\right)\,dx\]

Answer 10

ooo...now it clicks. thanks!!!