Question

PLEASE HELP!

Answer 1

JUST THE BOTTOM ONE....

Answer 2

The answer is choice C since this is the only one where the growth rate of g(x) is larger than the growth rate of f(x)

Answer 3

ok, can you explain to me how that helps? sorry, I don't understand what that has to do with the limit

Answer 4

use l'hospital's rule and derive the numerator ln(x) to get 1/x and derive the denominator e^x to get e^x


So we now have the fraction \[\frac{(1/x)}{e^x}\] which becomes \[\frac{1}{xe^x}\]


Hopefully you can see that the limit as x goes to infinity is 0.

Answer 5

what about e?

Answer 6

The term xe^x approaches infinity as x approaches infinity, so \[\frac{1}{xe^x}\] approaches 0 as x approaches infinity