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JUST THE BOTTOM ONE....
The answer is choice C since this is the only one where the growth rate of g(x) is larger than the growth rate of f(x)
ok, can you explain to me how that helps? sorry, I don't understand what that has to do with the limit
use l'hospital's rule and derive the numerator ln(x) to get 1/x and derive the denominator e^x to get e^x So we now have the fraction \[\frac{(1/x)}{e^x}\] which becomes \[\frac{1}{xe^x}\] Hopefully you can see that the limit as x goes to infinity is 0.
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what about e?
The term xe^x approaches infinity as x approaches infinity, so \[\frac{1}{xe^x}\] approaches 0 as x approaches infinity
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