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OpenStudy (anonymous):
Compute the intergral of (sin x)/(1+cos x)^0.5
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OpenStudy (anonymous):
say u = 1+ cosx du = -sinx
OpenStudy (dumbcow):
use substitution: u = 1 + cos(x) du = -sin(x) dx
OpenStudy (dumbcow):
ha 2 people agree..it must be good advice
OpenStudy (anonymous):
lol, yes :)
OpenStudy (dumbcow):
anyway the sin(x) on top will cancel this way
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OpenStudy (anonymous):
oh okay.Thanks:)
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