ok this one im not sure of
find the vertex, the line of symetry and the maximum or minimum value ofx and graph the function
f(x)=-(x+9)^2-7

Question

ok this one im not sure of 
find the vertex, the line of symetry and the maximum or minimum value ofx and graph the function 
f(x)=-(x+9)^2-7

anonymous · Answer

Now to find Max an Min ...Just Differentiate them

anonymous · Answer

Maximum is (-9, -7), which is also the vertex.
Line of symmetry is x = -9

anonymous · Answer

$$\frac{d f(x)}{dx} = -2(x +9) $$
$$\frac{d^2 f(x)}{dx^2} = -2$$

anonymous · Answer

Then Put f'(x) = 0

-2(x +9) = 0

which gives you x = -9

anonymous · Answer

Now as f"(x) is minimum x =-9 turns to be maximum

dumbcow · Answer

i dont think he is in a calculus class guys.
ok the quadratic equation is already in vertex form
$$y = a(x-h)^{2} + k$$
vertex = (h,k)
when a is negative you have a downward parabola or a maximum

anonymous · Answer

can anyone graph this so i can see what it looks like?

anonymous · Answer

Now, The Function will form a Parabola and x =-9 should be line of symmetry

anonymous · Answer

It's just a downward opening parabola with the vertex at (-9, -7)

dumbcow · Answer

go to 

graphcalc.com

anonymous · Answer

ok so line of symetry is -9 and the maximum/minimum value is -7

anonymous · Answer

maximum is -9