Question

ok this one im not sure of
find the vertex, the line of symetry and the maximum or minimum value ofx and graph the function
f(x)=-(x+9)^2-7

Answer 1

Now to find Max an Min ...Just Differentiate them

Answer 2

Maximum is (-9, -7), which is also the vertex.
Line of symmetry is x = -9

Answer 3

\[\frac{d f(x)}{dx} = -2(x +9) \]
\[\frac{d^2 f(x)}{dx^2} = -2\]

Answer 4

Then Put f'(x) = 0

-2(x +9) = 0

which gives you x = -9

Answer 5

Now as f"(x) is minimum x =-9 turns to be maximum

Answer 6

i dont think he is in a calculus class guys.
ok the quadratic equation is already in vertex form
\[y = a(x-h)^{2} + k\]
vertex = (h,k)
when a is negative you have a downward parabola or a maximum

Answer 7

can anyone graph this so i can see what it looks like?

Answer 8

Now, The Function will form a Parabola and x =-9 should be line of symmetry

Answer 9

It's just a downward opening parabola with the vertex at (-9, -7)

Answer 10

go to

graphcalc.com

Answer 11

ok so line of symetry is -9 and the maximum/minimum value is -7

Answer 12

maximum is -9