ok what about this one f(x)=2x^2-8x+13
Since its in standard form, use \[x = -\frac{b}{2a}\] for line of symmetry, then substitute it back in to find y to determine the vertex
i think 1 would be-2
be careful with the neg signs a double neg makes a positive
so then 2
yes, now plug it back in to get y
which would be a minimum value?
correct because the "x^2" coefficient is positive
5 for y which would be theline of symetry
good, line of symmetry is always vertical so it will be "x="
5
so vertex is at (2,5) graph goes upward draw a straight vertical line through vertex there is your line of symmetry
what would the graph for this one look like
it would not be downward
positive means up, negative means down it might help to plot another point try x = 1, y = 7 so plot a point at (2,5) then another point at (1,7) its symmetric so a 3rd point at (3,7) then draw a parabola going through these 3 points theres your graph
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